(y^3+3y-1)-(y^3+3y+5)=

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Solution for (y^3+3y-1)-(y^3+3y+5)= equation:


Simplifying
(y3 + 3y + -1) + -1(y3 + 3y + 5) = 0

Reorder the terms:
(-1 + 3y + y3) + -1(y3 + 3y + 5) = 0

Remove parenthesis around (-1 + 3y + y3)
-1 + 3y + y3 + -1(y3 + 3y + 5) = 0

Reorder the terms:
-1 + 3y + y3 + -1(5 + 3y + y3) = 0
-1 + 3y + y3 + (5 * -1 + 3y * -1 + y3 * -1) = 0
-1 + 3y + y3 + (-5 + -3y + -1y3) = 0

Reorder the terms:
-1 + -5 + 3y + -3y + y3 + -1y3 = 0

Combine like terms: -1 + -5 = -6
-6 + 3y + -3y + y3 + -1y3 = 0

Combine like terms: 3y + -3y = 0
-6 + 0 + y3 + -1y3 = 0
-6 + y3 + -1y3 = 0

Combine like terms: y3 + -1y3 = 0
-6 + 0 = 0
-6 = 0

Solving
-6 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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